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Power Rule:
- ∫xⁿ dx = (xⁿ⁺¹)/(n+1) + C (where n ≠ -1)
The power rule is your best friend for integrating polynomial terms. It simply states that to integrate x raised to the power of n, you add 1 to the exponent and divide by the new exponent. Just remember that n cannot be -1, because that would lead to division by zero. For example, if you have ∫x² dx, you would apply the power rule as follows: add 1 to the exponent (2 + 1 = 3) and divide by the new exponent (3), resulting in (x³)/3 + C. This rule is incredibly versatile and appears frequently in various calculus problems. Make sure you're comfortable applying it to different values of n, including fractions and negative numbers. It's also important to remember the constant of integration, C, which is always added to indefinite integrals.
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Constant Multiple Rule:
- ∫cf(x) dx = c∫f(x) dx
This rule allows you to pull a constant out of the integral, which can simplify the integration process. If you have a constant multiplying a function inside the integral, you can move the constant outside the integral sign. This makes the integral easier to handle, especially when the constant is a large or complicated number. For example, if you have ∫5x² dx, you can rewrite it as 5∫x² dx. Then, you can apply the power rule to ∫x² dx, which gives you (x³)/3. Finally, multiply the result by the constant 5 to get 5(x³)/3 + C. This rule is particularly helpful when dealing with integrals that have coefficients or when you want to isolate a more complex function within the integral.
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Sum/Difference Rule:
- ∫[f(x) ± g(x)] dx = ∫f(x) dx ± ∫g(x) dx
The sum/difference rule lets you break up integrals of sums or differences into individual integrals. This is super handy when you have a complex expression inside the integral that you can separate into simpler terms. For instance, if you have ∫(x² + 3x - 2) dx, you can break it down into ∫x² dx + ∫3x dx - ∫2 dx. Then, you can integrate each term separately using the power rule and the constant multiple rule. This rule makes it much easier to handle integrals with multiple terms, as it allows you to focus on each term individually. Remember to combine the constants of integration at the end to get a single constant, C. This rule is a fundamental tool for simplifying and solving complex integrals.
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Integral of 1/x:
- ∫(1/x) dx = ln|x| + C
This is a special case because the power rule doesn't apply when n = -1. The integral of 1/x is the natural logarithm of the absolute value of x. The absolute value is crucial because the natural logarithm is only defined for positive values. Therefore, you must take the absolute value of x to ensure that the logarithm is always defined. This formula is essential for integrating rational functions that have x in the denominator. For example, if you have ∫(5/x) dx, you can use the constant multiple rule to rewrite it as 5∫(1/x) dx, and then apply the integral of 1/x to get 5ln|x| + C. This formula is a cornerstone of calculus and is used extensively in various applications.
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Integral of eˣ:
- ∫eˣ dx = eˣ + C
The integral of the exponential function eˣ is simply eˣ, plus the constant of integration. This is one of the easiest integrals to remember because the exponential function is its own derivative and integral. When you integrate eˣ, you get eˣ back, which is quite remarkable. This formula is fundamental in calculus and is used extensively in physics, engineering, and other fields. For example, if you have ∫2eˣ dx, you can use the constant multiple rule to rewrite it as 2∫eˣ dx, and then apply the integral of eˣ to get 2eˣ + C. The exponential function appears in many real-world phenomena, such as exponential growth and decay, making this integral essential for modeling and understanding these processes.
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Integral of sin(x):
- ∫sin(x) dx = -cos(x) + C
The integral of sin(x) is -cos(x) plus the constant of integration. This is a fundamental formula in calculus that you'll use frequently. When you differentiate -cos(x), you get sin(x), which confirms that -cos(x) is indeed the integral of sin(x). This integral is essential for solving problems involving trigonometric functions, such as those found in physics, engineering, and mathematics. For example, if you have ∫3sin(x) dx, you can use the constant multiple rule to rewrite it as 3∫sin(x) dx, and then apply the integral of sin(x) to get -3cos(x) + C. Make sure you remember the negative sign, as it's a common mistake to forget it. Mastering this integral will significantly enhance your ability to solve trigonometric problems.
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Integral of cos(x):
- ∫cos(x) dx = sin(x) + C
The integral of cos(x) is sin(x) plus the constant of integration. This is another fundamental formula that you'll use extensively in calculus. When you differentiate sin(x), you get cos(x), which confirms that sin(x) is the integral of cos(x). This integral is essential for solving problems involving trigonometric functions, such as those found in physics, engineering, and mathematics. For example, if you have ∫5cos(x) dx, you can use the constant multiple rule to rewrite it as 5∫cos(x) dx, and then apply the integral of cos(x) to get 5sin(x) + C. Remembering this integral is crucial for tackling a wide range of calculus problems.
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Integral of sec²(x):
- ∫sec²(x) dx = tan(x) + C
The integral of sec²(x) is tan(x) plus the constant of integration. This formula is derived from the fact that the derivative of tan(x) is sec²(x). Knowing this integral is particularly useful when dealing with trigonometric identities and substitutions. It often appears in problems involving the integration of trigonometric functions and their powers. For example, if you have ∫2sec²(x) dx, you can use the constant multiple rule to rewrite it as 2∫sec²(x) dx, and then apply the integral of sec²(x) to get 2tan(x) + C. This integral is an important tool in your calculus arsenal.
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Integral of csc²(x):
- ∫csc²(x) dx = -cot(x) + C
The integral of csc²(x) is -cot(x) plus the constant of integration. This formula is derived from the fact that the derivative of -cot(x) is csc²(x). This integral is commonly used in problems involving trigonometric functions, especially when dealing with cotangent and cosecant functions. For example, if you have ∫4csc²(x) dx, you can use the constant multiple rule to rewrite it as 4∫csc²(x) dx, and then apply the integral of csc²(x) to get -4cot(x) + C. Don't forget the negative sign, as it's an easy mistake to make. Familiarity with this integral is essential for solving various calculus problems.
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Integral of sec(x)tan(x):
- ∫sec(x)tan(x) dx = sec(x) + C
The integral of sec(x)tan(x) is sec(x) plus the constant of integration. This formula is derived from the fact that the derivative of sec(x) is sec(x)tan(x). This integral is frequently encountered in calculus problems involving trigonometric functions. For example, if you have ∫7sec(x)tan(x) dx, you can use the constant multiple rule to rewrite it as 7∫sec(x)tan(x) dx, and then apply the integral of sec(x)tan(x) to get 7sec(x) + C. This integral is a valuable tool for simplifying and solving complex trigonometric integrals.
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Integral of csc(x)cot(x):
- ∫csc(x)cot(x) dx = -csc(x) + C
The integral of csc(x)cot(x) is -csc(x) plus the constant of integration. This formula is derived from the fact that the derivative of -csc(x) is csc(x)cot(x). This integral is commonly used in calculus problems involving trigonometric functions, especially when dealing with cotangent and cosecant functions. For example, if you have ∫-3csc(x)cot(x) dx, you can use the constant multiple rule to rewrite it as -3∫csc(x)cot(x) dx, and then apply the integral of csc(x)cot(x) to get 3csc(x) + C. Remembering the negative sign is crucial, as it's easy to overlook. Familiarity with this integral is essential for solving various calculus problems.
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Integral of aˣ:
- ∫aˣ dx = (aˣ)/ln(a) + C
Where a is a positive constant not equal to 1. This formula extends the basic exponential integral to cases where the base is not e. To integrate aˣ, you divide aˣ by the natural logarithm of a, and then add the constant of integration. This formula is useful for integrating exponential functions with different bases. For example, if you have ∫2ˣ dx, you would apply this formula as follows: (2ˣ)/ln(2) + C. This integral is an important tool for handling exponential functions with various bases.
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Integral of logₐ(x):
- ∫logₐ(x) dx = xlogₐ(x) - x/ln(a) + C
Where a is a positive constant not equal to 1. This formula is used to integrate logarithmic functions with any base. To integrate logₐ(x), you multiply x by logₐ(x), subtract x divided by the natural logarithm of a, and then add the constant of integration. This formula is particularly useful when dealing with logarithms in various contexts. For example, if you have ∫log₂(x) dx, you would apply this formula as follows: xlog₂(x) - x/ln(2) + C. This integral is an essential tool for handling logarithmic functions with different bases.
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Integral of sinh(x):
- ∫sinh(x) dx = cosh(x) + C
The integral of sinh(x) is cosh(x) plus the constant of integration. This is a fundamental formula in calculus that you'll use frequently. The hyperbolic sine function, sinh(x), is defined as (eˣ - e⁻ˣ)/2, and its integral is the hyperbolic cosine function, cosh(x), which is defined as (eˣ + e⁻ˣ)/2. This integral is essential for solving problems involving hyperbolic functions, such as those found in physics and engineering. For example, if you have ∫3sinh(x) dx, you can use the constant multiple rule to rewrite it as 3∫sinh(x) dx, and then apply the integral of sinh(x) to get 3cosh(x) + C. Make sure you remember this integral, as it's a key component in various calculus problems.
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Integral of cosh(x):
- ∫cosh(x) dx = sinh(x) + C
The integral of cosh(x) is sinh(x) plus the constant of integration. This is another fundamental formula that you'll use extensively in calculus. The hyperbolic cosine function, cosh(x), is defined as (eˣ + e⁻ˣ)/2, and its integral is the hyperbolic sine function, sinh(x), which is defined as (eˣ - e⁻ˣ)/2. This integral is essential for solving problems involving hyperbolic functions, such as those found in physics and engineering. For example, if you have ∫5cosh(x) dx, you can use the constant multiple rule to rewrite it as 5∫cosh(x) dx, and then apply the integral of cosh(x) to get 5sinh(x) + C. Remembering this integral is crucial for tackling a wide range of calculus problems.
- ∫ₐᵇ f(x) dx = F(b) - F(a), where F(x) is the antiderivative of f(x).
- Practice: The more you use these formulas, the easier they'll be to remember.
- Flashcards: Create flashcards with the formulas and their applications.
- Mnemonics: Develop memory aids to help you recall the formulas.
- Understand the Derivations: Knowing where the formulas come from can make them easier to remember.
Hey guys! Having trouble with definite integrals? Don't worry, you're not alone. Integrals can be tricky, but with the right formulas and a bit of practice, you'll be solving them like a pro in no time. This article is designed to be your go-to definite integral formula sheet, providing you with a quick and easy reference for all the essential formulas you need. We'll break down the formulas, explain their applications, and give you some tips to help you remember them. So, let's dive in and conquer those integrals!
Basic Definite Integral Formulas
Let's kick things off with the fundamental formulas you'll use constantly. These are the building blocks for more complex integrals, so make sure you have them down cold. Knowing these formulas is like having a superpower when it comes to calculus. Seriously, mastering these will make your life so much easier, and you'll be able to tackle more advanced problems with confidence. Think of these as your essential tools in your integral-solving toolkit. Now, let's dive into each one and see why they're so important. Remember, practice makes perfect, so don't be afraid to try out these formulas on different problems.
Trigonometric Integral Formulas
Trigonometric functions pop up everywhere in calculus, so you'll need to know their integrals like the back of your hand. These formulas might seem a bit intimidating at first, but with practice, you'll memorize them in no time. Understanding these integrals is crucial for solving problems related to oscillations, waves, and periodic phenomena. So, let's break down each formula and see how they can be applied in different contexts. Remember, familiarity with these integrals will significantly enhance your problem-solving skills.
Exponential and Logarithmic Integral Formulas
Beyond the basic exponential function eˣ, you might encounter other exponential and logarithmic functions. Here are their integral formulas:
Hyperbolic Integral Formulas
Hyperbolic functions are combinations of exponential functions, and they have their own set of integral formulas:
Definite Integrals
Definite integrals are integrals with upper and lower limits. They give you a numerical value, representing the area under a curve between those limits. The Fundamental Theorem of Calculus links definite and indefinite integrals:
To evaluate a definite integral, find the antiderivative of the function, then evaluate it at the upper and lower limits of integration, and subtract the values.
Tips for Remembering Formulas
Conclusion
So there you have it, guys! A comprehensive definite integral formula sheet to help you conquer calculus. Keep this guide handy, practice regularly, and you'll be solving integrals like a champ. Remember, calculus is all about practice, so don't be afraid to dive in and get your hands dirty. Good luck, and happy integrating!
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